2
22
2016
0

[BZOJ3673&3674] 可持久化并查集 by zky & 可持久化并查集加强版

两个都是可持久化线段树,相当于复习一下算法。。

第一个程序我没加路径压缩,第二个加了

第二个读入的操作编号不要异或lastans……在这里卡了一下

#include<cstdio>
#include<algorithm>
using namespace std;

struct SegTree{
int l,r,ls,rs,v;
}tree[2000005];

int root[20005],cnt,deep[200005],n,m;

void Build(int &rt,int l,int r){
if(!rt)rt=++cnt;
if(l==r){tree[rt].v=l;return;}
int mid=l+r>>1;
tree[rt].l=l;
tree[rt].r=r;
Build(tree[rt].ls,l,mid);
Build(tree[rt].rs,mid+1,r);
}

void Change(int x,int &y,int pos,int val){
y=++cnt;
tree[y].l=tree[x].l;
tree[y].r=tree[x].r;
if(tree[x].l==tree[x].r){tree[y].v=val;deep[y]=deep[x];return;}
tree[y].ls=tree[x].ls;
tree[y].rs=tree[x].rs;
int mid=tree[x].l+tree[x].r>>1;
if(pos<=mid)Change(tree[x].ls,tree[y].ls,pos,val);
if(pos>mid)Change(tree[x].rs,tree[y].rs,pos,val);
}

int Query(int rt,int pos){
if(tree[rt].l==tree[rt].r)return rt;
int mid=tree[rt].l+tree[rt].r>>1;
if(pos<=mid)return Query(tree[rt].ls,pos);
if(pos>mid)return Query(tree[rt].rs,pos);
}

void Add(int rt,int pos){
if(tree[rt].l==tree[rt].r){deep[rt]++;return;}
int mid=tree[rt].l+tree[rt].r>>1;
if(pos<=mid)Add(tree[rt].ls,pos);
if(pos>mid)Add(tree[rt].rs,pos);
}

int Find(int rt,int x){
int tp=Query(rt,x);
if(x==tree[tp].v)return tp;
return Find(rt,tree[tp].v);
}

int main(){
freopen("3673.in","r",stdin);
freopen("3673.out","w",stdout);
scanf("%d %d",&n,&m);
Build(root[0],1,n);
for(int i=1;i<=m;i++){
    int opt;
    scanf("%d",&opt);
    if(opt==1){
		int x,y,px,py;
        scanf("%d %d",&x,&y);
        root[i]=root[i-1];
        px=Find(root[i],x);py=Find(root[i],y);
        if(tree[px].v==tree[py].v)continue;
        if(deep[px]>deep[py])swap(px,py);
        Change(root[i-1],root[i],tree[px].v,tree[py].v);
        if(deep[px]==deep[py])Add(root[i],tree[py].v);
    }
    if(opt==2){
		int k;
		scanf("%d",&k);
		root[i]=root[k];
    }
    if(opt==3){
		int x,y;
		root[i]=root[i-1];
		scanf("%d %d",&x,&y);
		if(tree[Find(root[i],x)].v!=tree[Find(root[i],y)].v)puts("0");
		else puts("1");
    }
}
return 0;
}
#include<cstdio>
#include<algorithm>
using namespace std;

int n,m,cnt,lastans=0,deep[10000005],root[200005];

struct SegTree{
int l,r,ls,rs,v;
}tree[10000005];

void Build(int &rt,int l,int r){
if(!rt)rt=++cnt;
tree[rt].l=l;
tree[rt].r=r;
if(l==r){tree[rt].v=l;return;}
int mid=l+r>>1;
Build(tree[rt].ls,l,mid);
Build(tree[rt].rs,mid+1,r);
}

void Change(int x,int &y,int pos,int val){
y=++cnt;
tree[y].l=tree[x].l;
tree[y].r=tree[x].r;
if(tree[x].l==tree[x].r){tree[y].v=val;deep[y]=deep[x];return;}
tree[y].ls=tree[x].ls;
tree[y].rs=tree[x].rs;
int mid=tree[x].l+tree[x].r>>1;
if(pos<=mid)Change(tree[x].ls,tree[y].ls,pos,val);
if(pos>mid)Change(tree[x].rs,tree[y].rs,pos,val);
}

void Add(int rt,int pos){
if(tree[rt].l==tree[rt].r){deep[rt]++;return;}
int mid=tree[rt].l+tree[rt].r>>1;
if(pos<=mid)Add(tree[rt].ls,pos);
if(pos>mid)Add(tree[rt].rs,pos);
}

int Query(int rt,int pos){
if(tree[rt].l==tree[rt].r){return rt;}
int mid=tree[rt].l+tree[rt].r>>1;
if(pos<=mid)return Query(tree[rt].ls,pos);
if(pos>mid)return Query(tree[rt].rs,pos);
}

int Find(int rt,int x){
int p=Query(rt,x);
if(x==tree[p].v){return p;}
int tp=Find(rt,tree[p].v);
Change(rt,rt,tree[p].v,tp);
return tp;
}

int main(){
freopen("3674.in","r",stdin);
freopen("3674.out","w",stdout);
scanf("%d %d",&n,&m);
Build(root[0],1,n);
for(int i=1;i<=m;i++){
    int opt;
    scanf("%d",&opt);
    if(opt==1){
		int x,y,p,q;
		scanf("%d %d",&x,&y);
		x^=lastans;y^=lastans;
        root[i]=root[i-1];
        p=Find(root[i],x);
        q=Find(root[i],y);
        if(tree[p].v==tree[q].v)continue;
        if(deep[p]>deep[q])swap(p,q);
        Change(root[i-1],root[i],tree[p].v,tree[q].v);
        if(deep[p]==deep[q])Add(root[i],tree[q].v);
    }
    if(opt==2){
		int k;
		scanf("%d",&k);
		k^=lastans;
        root[i]=root[k];
    }
    if(opt==3){
		int x,y;
		scanf("%d %d",&x,&y);
		x^=lastans;y^=lastans;
		root[i]=root[i-1];
        if(tree[Find(root[i],x)].v==tree[Find(root[i],y)].v){puts("1");lastans=1;}
        else {puts("0");lastans=0;}
	}
}
return 0;
}
Category: BZOJ | Tags: OI bzoj | Read Count: 424

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