练一下python
以下代码在python2.7编译通过
这个题直接做，循环就可以了
win=[[1, 0, 2, 2, 0], [2, 1, 0, 2, 0], [0, 2, 1, 0, 2], [0, 0, 2, 1, 2], [2, 2, 0, 0, 1]]
xiaoa=[]; xiaob=[]; wina=0; winb=0
n, na, nb=map(int, raw_input().split())
#print n, na, nb
p=raw_input().split()
for i in range(0, na):
xiaoa.append(int(p[i]))
p=raw_input().split()
for i in range(0, nb):
xiaob.append(int(p[i]))
for i in range(0, n):
px=win[int(xiaoa[i%na])][int(xiaob[i%nb])]
if px==0:
winb+=1
elif px==2:
wina+=1
print wina, winb
