10
22
2015
0

[BZOJ1801] [Ahoi2009] chess 中国象棋

有几天没写题解了啊……

这几天在复习以前写过的题目。以后隔一阵子也要去看一看。

记忆化搜索大法好!

#include<cstdio>
#include<cstring>

const long long MOD=9999973;
long long n,m,f[105][105][105],c[105][105];

long long C(long long i,long long j){
	if(j==0)return 1;
	if(i==0)return 0;
	if(i==1)return j==1?1:0;
	if(j==1)return i;
	if(c[i][j]!=-1)return c[i][j];
	return c[i][j]=(C(i-1,j-1)%MOD+C(i-1,j)%MOD)%MOD;
}

long long dfs(long long a,long long b,long long c){
	if(a>n)return 1;
	if(f[a][b][c]!=-1)return f[a][b][c];
	f[a][b][c]=dfs(a+1,b,c)%MOD;
	if(c>=1){
		f[a][b][c]=(f[a][b][c]+dfs(a+1,b+1,c-1)%MOD*c%MOD)%MOD;
	}
	if(m-b-c>=1){
		f[a][b][c]=(f[a][b][c]+dfs(a+1,b,c+1)%MOD*(m-b-c)%MOD)%MOD;
		f[a][b][c]=(f[a][b][c]+dfs(a+1,b+1,c)%MOD*(m-b-c)%MOD*c%MOD)%MOD;
	}
	if(c>=2){
		f[a][b][c]=(f[a][b][c]+dfs(a+1,b+2,c-2)%MOD*C(c,2)%MOD)%MOD;
	}
	if(m-b-c>=2){
		f[a][b][c]=(f[a][b][c]+dfs(a+1,b,c+2)%MOD*C(m-b-c,2)%MOD)%MOD;
	}
	return f[a][b][c];
}

int main(){
	freopen("1801.in","r",stdin);
	freopen("1801.out","w",stdout)
	scanf("%lld %lld",&n,&m);
	memset(f,-1,sizeof(f));
	memset(c,-1,sizeof(c));
	printf("%lld\n",dfs(1,0,0));
	return 0;
}
Category: BZOJ | Tags: bzoj | Read Count: 527

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